Learn Odds in Math

Introduction to learn odds in math:

A number which is not divisible by two is called as odd number in math. This is considered as whole number. The odd numbers are represented in set as { 1, 3, 5, 7, 9,……} and it does not contain multiples of two in math. We can learn the odds by identify the last digit that is if the last digit is 1,3 ,5 ,7 and so on means that number is odd.


Explanation for odd in math


Learn odd in math:

We can learn odd number’s arithmetic operations by using some results. They are,

In addition and subtraction:

If we add the even number and odd number means the resultant value is odd.For example add the numbers 8 + 1 = 9.

If we add the two odd numbers means the resultant value is even. For example add the 5 + 7 = 12.

In multiplication:

If we multiply the even and odd numbers means the resultant value is even. For example multiply the 6 x 7 = 42.

If we multiply the two odd numbers means the resultant value is odd. For example multiply the numbers 3 and 5 and we get the answer as odd value 15.

In other words:

The odd numbers are also called as gnomonic numbers in math. It is in the form as n = 2k + 1. Here integer is k. We can learn odd numbers by using this form. If we want to identify the odd numbers means divide that number by 2 and if we get the remainder, that number is odd.

The odd numbers are generated by using function as `(x(1 + x))/(1 + x)`  = x + 3x2 + 5x3 +......

Understanding exponential math problems is always challenging for me but thanks to all math help websites to help me out.

Learn odd numbers with example:


Problem 1: Find the odd numbers  from given set

{ 3, 6, 14, 7, 21, 34, 22, 47 }.

Answer:

The odd numbers are { 3, 7, 21, 47 }. Because these numbers are ended with 1,3, 7 and it does not divided by two.

Problem 2: Add and multiply the following odd numbers:

3 + 9 = 12.

53 + 7 = 60.

33 x 5 = 165.

Exercise problem for odd numbers:

Find the odd number from set { 190, 321, 453, 628 }.

Answer: { 321, 453 }.

Definition Reflexive Math

Introduction:

Reflexive is one of the properties in math. It is one of the postulates in equality. Reflexive property means anything equals to itself that is a = a where a is the set of numbers or number. Using reflexive property many geometric proofs were proved. Since it has equality we can find the answer for the given expressions.

Is this topic Sum of Squares Formula hard for you? Watch out for my coming posts.

Example problems - Definition reflexive math:

Example 1 - Definition reflexive math:

Use the reflexive property to find the answer for x and the expressions are x+9 and 2x+8.

Solution:

The given expressions are x+9 and 2x+8

We the reflexive property anything equals to same thing

So, the expression can be written as x+9=2x+8

Add –x on both sides in the above equation

X+9+(-x) =2x+8+(-x)

X+9-x = 2x+8-x

9=x+8

Now subtract 8 on both sides

9-8=x+8-8

1=x

The value of x is 1.

Example 2 - Definition reflexive math:

Use the reflexive property to find the answer for y and the expressions are 2y+8 and y+8.

Solution:

The given expressions are 2y+8 and y+8.

We the reflexive property anything equals to same thing

So, the expression can be written as 2y+8 = y+8.

Add –y on both sides in the above equation

2y+8 +(-y)= y+8+(-y)

2y+8-y=y+8-y

y+8=8

Now subtract 8 on both sides

y+8-8=8-8

y=0

I have recently faced lot of problem while learning solve my math word problem, But thank to online resources of math which helped me to learn myself easily on net.

More Example problems - Definition reflexive math:


Example 3 - Definition reflexive math:

Use the reflexive property to find the answer for x and the expressions are 3x+9 and 2x+8.

Solution:

The given expressions are 3x+9 and 2x+8

We the reflexive property anything equals to same thing

So, the expression can be written as 3x+9=2x+8

Add –xx on both sides in the above equation

3x+9+(-2x) =2x+8+(-2x)

3x+9-2x = 2x+8-2x

x+9 =8

Now subtract 9 on both sidesx

x+9-9=8-9

x=-1

The value of x is -1.

Example 4 - Definition reflexive math:

Use the reflexive property to find the answer for y and the expressions are 2y+8 and4y+8.

Solution:

The given expressions are 2y+8 and 4y+8.

We the reflexive property anything equals to same thing

So, the expression can be written as 2y+8 = 4y+8.

Add –2y on both sides in the above equation

2y+8 +(-2y)= 4y+8+(-2y)

8=2y+8

Now subtract 8 on both sides

8-8 =2y+8-8

2y=0

So, y=0.

Maximum Math Terms

Introduction to maximum math terms:
The math term maximum is define different kinds of versions. They are find out the maximum value from given data, determine the maximum distance between two points and the maximum value of set theory function. The greatest value is defined in math as maximum. The integration is used for find out the maximum value in set element.


Explanation for terms maximum in math


Procedures for finding the maximum value in math:

Step 1: Collect the set of data and use the comparison method.

Step 2: The comparison method is arrange the numbers in ascending order.

Step 3: At last find the maximum number from above order of data.

For example take  the set of data as 4, 2, 1, 6, 12, 3, 10. The comparison method is used for data arrangement in ascending order. The elements in ascending order is 1, 2, 3, 4, 6, 10, 12. The greatest value of given set of data is 12.

Maximum in other branch of math terms:

The set operations are used for finding the maximum value in functions. In math the optimization is determine the maxima from set of data and the real valued function is explain the global maximum. The bounded value theorem is essential one for global maximum determination.

In terms maxima, the expression A = { ai }N is explain the maxima for set of elements. The last element of this order is denote the maximum value of set.  The order statistics has different types and this is one type of statistics.

Consider the example as { 1, 5, 8, 4 } and arrange the set of data in ascending order as { 1, 4, 5, 8 }.Finally, the maximum value of set is 8.

Maximum in profit:

The term maximum in profit is how much of profit the company get.

I have recently faced lot of problem while learning Interest Problems, But thank to online resources of math which helped me to learn myself easily on net.

Examples for maximum in math terms


Problem 1:

Find the maximum value from the set of numbers 8, 4, 1, 20, 15, 9.

Answer:

Arrange the set of numbers in ascending order as 1, 4, 8, 9, 15, 20.

Set’s maximum value is 20.

Problem 2:

Find the maximum profit from P = 6x – 0.04x^2.

Answer:

If `(dP)/dx` = 0 then 6 – 0.08x = 0

`(d^2P)/(dx^2)` = -0.08 it has maximum profit.

If x = 200, profit is 400.

Excercise for maximum terms in mat:

1. Find out the maximum from given set of data { 12, 15, 11, 22, 9 }.

Answer: Maximum value of set is 22.

2. Find out the maximum value from set of numbers: 110, 120, 108, 115.

Answer: The minimum value is 120.

Video Tutorials for Math

Introduction about video tutorials for math:

Math is very interesting and complicated subject. We have various types of method and procedures to solve the math question. Tutorial is one of the techniques to improve the student’s knowledge. Students can learn their own speed, and their convenience. Interactive classes can do by a tutor during tutorials. One of the main benefits is, students clarify their doubts frankly as well as immediately. Here we are going to learn about some example problems of tutorials for math.

Having problem with Derivative Product Rule keep reading my upcoming posts, i will try to help you.

Example problems of video tutorials for math:


Example 1:

A train takes to travels 200 miles in 4 hours. How long the train travels in 8 hours?

Solution:

Step 1: We know that the train travel 200 miles. If a train travel 8 hours how many miles the train travel?

Step 2: it’s the direct proportionality.

Step 3: We know that

Hour’s         miles

4               200

8                 x

Step 4: Now we need to solve the value of x using cross multiplication. So, we get 4x= 1600

Step 5: Divide using 4 on both the sides. So, the train travelled 400 miles.

Example 2:

Using these lines. Find the intersecting points?

y = 2y+2

y = x+12

Solution:

Step 1:

y = 2x+2      ------------> ( 1 )

y = x+12      -------------> ( 2 )

Step 2:

We know that the two lines are equal. So, it can be written as ,2x + 2 = x + 12

Step 3:  Here we need to solve the value of x. So, 2x – x = 12 – 2.Therefore, the value of x is 10

Step 4:

Substituting the value of x=10 in equation (1)

y = 2x + 2

= 2 ( 10 ) + 2

= 20 + 2   = 22

y = 22

The two given two lines intersect at a point (10, 22)

This is the example of intersecting lines.

These are the example problems of video tutorials for math .

Please express your views of this topic need help with math problems for free by commenting on blog.

One more example of video tutorials for math:


Example 3:

The sum of the least and greatest of 3 consecutive integers is 160. What are the values of the 3 integers?

Solution:

Step 1: Let us assume the integers are x,x+1 and x+2 .

Step 2: And we know that , the least and greatest of the 3 consecutive integer is 160 .

Step 3: So, we can arrange the equation, that is x+(x+2) = 160 .

Step 4: Here we need to solve this equation. So 2x+2 = 160. (Subtract 2 on both the sides)

Step 5: Therefore x= 79. Therefore the least integer is 79.

Step 6: Substitute the x value is x+1, x+2 .

Step 7: Therefore, 79+1 = 80 and 79+2= 81.

Step 8: Therefore, the values of 3 integers are 79, 80 and 81.

These are the examples of video tutorials for math.

Math Skills Practice

Basic Math Definition:

Arithmetic is the one of the Basic mathematics definition. Arithmetic deals with the properties of numbers and ways of combining them through addition (+), subtraction (-), multiplication (*), and division (/) And basic math definition are contain with the arithmetic, Fractions, Decimals, Roots, Exponents, Factorials, Modular and Interval Arithmetic these are the contains with the basic math definition.

Having problem with Interquartile Range Definition keep reading my upcoming posts, i will try to help you.

Basic Math Definition Examples:


Arithmetic practice Examples:

Adding Arithmetic Example:

56977 + 21454

56977
+ 21454
---------
78431
---------
Subtracting Arithmetic Example:

782138 – 574121

782138
( - )    574121
----------
208017
----------
Multiplication Arithmetic Example:

875 x 69

875 x 69
-------------
7 8 7 5
5 2 5 0
-------------
6 0 37 5
-------------
Division Arithmetic Example:

45` -: ` 9

9) 45 (5
45
------
0
------

Please express your views of this topic help with math word problems for free by commenting on blog.

Fractions practice Examples:


Fraction practice Example 1:

Add Two Fractions  ` 5/6 + 9/8`

Step 1:

For the denominators here, the 6 and 8, a common denominator for both is 24.

Step 2:

With the common denominator, the `5/6` becomes a `20/24 ` and the  `9/8 ` becomes a `27/24`

So, the problem here is to add `20/24` and `27/24`

Step 3:

The two denominators are same adding numerator values then ,we get  `47/24`

Step 4:

The fraction `47/24` is an improper fraction (the numerator is greater than the denominator).
Step 5:

The whole number part of the mixed number is found by dividing the 47 by the 24.

Step 6:

The fractional element of the mixed number is found by using the remainder of the division, which in this case is 23 (47 divided by 24 is 1 remainder 23).

Answer:

`1 23/24`

Reduce the fraction Practice Example:

Reduce the given factor 6/63

Solution:

The fraction `6/63` is not reduced to lowest terms. We can decrease this fraction to lowest terms by dividing both the numerator and denominator by 3.

Greatest Common Factor (GCF) of the numbers 6 and 63. So, this fraction reduced to lowest terms is `2/21`

Answer:  ` 2/21`

Subtracting the Fraction Practice example:

Subtracting the given fraction `8/5` and` 3/5`

Solution:

Step 1:

The given faction denominators (5) are equal.

Step 2:

Therefore the fraction, `5 /5` can be reduced further to 1, because anything over itself (other than zero) is 1.

Step 3:

The fraction 1 is not reduced to lowest terms. We can decrease this fraction to lowest terms by dividing both the numerator and denominator by 5.

Step 4:

Greatest Common Factor (GCF) of the numbers 0 and 5.

So, this fraction reduced to lowest terms is 1

Answer

The subtracting fraction is 1

Fog and Gof Math Problems

Introduction to fog and gof math problems:
Basically fog and gof math problems are nothing but we have to convert the one function into other function. If the given function is in the form of f(x) mean we have to convert this into f (g (x)) form. If the given function is in the g (x) form then we have to change this into g (f (x)) form.  Let us see some example for these types of problems.


Example for fog and gof math problems


Example 1:

Find the fog and gof for the given math problems. Where f (x) = x and g (x) = 3x + 4

Solution:

First we have to find fog for the given problem.  For that first we have to find the g(x).

Where g (x) = 3x + 4

fog = f (g (x)) = f (3x + 4) = 3x + 4

Likewise we have to find gof for the given math problem.

gof mean first we have to find f(x)

Where f (x) = x

Then gof = g (f (x)) = g (x) = 3x +4

From the above we understand we have to write the output of the one function value into the other function form.

Understanding Graphing Quadratic Functions in Standard Form is always challenging for me but thanks to all math help websites to help me out.

Example 2:


Find the fog and gof for the given math problems. Where f(x) = 2x + 5 and g(x) = 5x

Solution:

First we have to find fog for the given problem.  For that first we have to find the g(x).

Where g (x) = 5x

fog = f (g (x)) = f (5x) = 2(5x) + 5

= 10x + 5

Likewise

gof mean first we have to find f(x)

Where f (x) = 2x + 5

Then gof = g (f (x)) = g (2x + 5) = 5(2x + 5)

= 10x + 25

If suppose we are having the square or cubic function mean we have to find the square or cubic roots. After that we have to expand the function. From the above there is no square or cubic value. So we just find the function values.

Math Percent Help Now

Introduction to percentage:

In Math subject, a percent (percentage) is one way of expressing a number as a fraction number of 100. It means one per hundred. The percent is using the sign “%”. Example, 69% (to read this number  “sixty-nine percent”) is equal to 69 / 100, otherwise 0.69. So, in this way of math percent help now for us. The percentage sign or symbol is “%”.

Please express your views of this topic Fraction on a Number Line by commenting on blog.

Math Percent help:


The percentages are mostly helpful now, it is used and expressed how large quantity and small quantity is, related to another quantity. It has using two quantities; usually the first quantity represents the part of second quantity. And it should be greater than zero.

Example:

Increase of  `$ 0.15` on a rate of `$1.50 ` an increase by a fraction of 0.15 / 1.50 = 0.1. So, that 0.1 * 100 = 10%, as a percentage expressed as, this is a 10% increase.

And also percentages helps to find and express numbers between zero and one, any dimensionless proportionality can be expressed as a percentage. For example, 129% is 1.29 and -0.29% is -0.0029.


Calculate the percentage:


The concept of performing calculations with percentages is, the percent symbol can be treated as being equivalent to the number constant 1 / 100 = 0.01. , for an example 75% of 400 can be written as (75 / 100) × 400 = 300.

Unit represents:

To find the percentage of a unit represents out of a whole of N units, divide 100% by N. For suppose, if we have 125 apples, and we want to find out what percentage of these 125 apples.

In a single apple represents, 100 / 125 = (100 / 125) % the answer of 0.8%.

So, if you give away one apple, you have given away 0.8% of the apples we had.

Then, if we give away 100 apples, we have given away 100 × 0.8% = 80% of us 125 apples.

Is this topic Dividing Whole Numbers and Fractions hard for you? Watch out for my coming posts.

Example problems in math percentage:

Example 1:

What is the answer for 300% of 40?

Solution:

300% × 40 = (300 / 100) × 40 = 120.

Answer is 120.

Example 2:

What is the solution of 15% of 75?

Solution:

15% × 75 = (15 / 100) × 75 = 11.25

Answer is 11.25.

Example 3:

75% of all college students are male. There are 1500 male students. How many (total) students are in the college?

Solution:

1500 = 75% × X, therefore X = (1500 / (75 / 100)) = 2000.

Answer is 2000.